Optimal. Leaf size=87 \[ -\frac{x \left (8 a^2+20 a b+15 b^2\right )}{8 b^3}+\frac{(a+b)^{5/2} \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (x)}{\sqrt{a}}\right )}{\sqrt{a} b^3}-\frac{(4 a+7 b) \sin (x) \cos (x)}{8 b^2}-\frac{\sin (x) \cos ^3(x)}{4 b} \]
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Rubi [A] time = 0.1869, antiderivative size = 87, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.4, Rules used = {3191, 414, 527, 522, 203, 205} \[ -\frac{x \left (8 a^2+20 a b+15 b^2\right )}{8 b^3}+\frac{(a+b)^{5/2} \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (x)}{\sqrt{a}}\right )}{\sqrt{a} b^3}-\frac{(4 a+7 b) \sin (x) \cos (x)}{8 b^2}-\frac{\sin (x) \cos ^3(x)}{4 b} \]
Antiderivative was successfully verified.
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Rule 3191
Rule 414
Rule 527
Rule 522
Rule 203
Rule 205
Rubi steps
\begin{align*} \int \frac{\cos ^6(x)}{a+b \sin ^2(x)} \, dx &=\operatorname{Subst}\left (\int \frac{1}{\left (1+x^2\right )^3 \left (a+(a+b) x^2\right )} \, dx,x,\tan (x)\right )\\ &=-\frac{\cos ^3(x) \sin (x)}{4 b}+\frac{\operatorname{Subst}\left (\int \frac{a+4 b-3 (a+b) x^2}{\left (1+x^2\right )^2 \left (a+(a+b) x^2\right )} \, dx,x,\tan (x)\right )}{4 b}\\ &=-\frac{(4 a+7 b) \cos (x) \sin (x)}{8 b^2}-\frac{\cos ^3(x) \sin (x)}{4 b}+\frac{\operatorname{Subst}\left (\int \frac{4 a^2+9 a b+8 b^2-(a+b) (4 a+7 b) x^2}{\left (1+x^2\right ) \left (a+(a+b) x^2\right )} \, dx,x,\tan (x)\right )}{8 b^2}\\ &=-\frac{(4 a+7 b) \cos (x) \sin (x)}{8 b^2}-\frac{\cos ^3(x) \sin (x)}{4 b}+\frac{(a+b)^3 \operatorname{Subst}\left (\int \frac{1}{a+(a+b) x^2} \, dx,x,\tan (x)\right )}{b^3}-\frac{\left (8 a^2+20 a b+15 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\tan (x)\right )}{8 b^3}\\ &=-\frac{\left (8 a^2+20 a b+15 b^2\right ) x}{8 b^3}+\frac{(a+b)^{5/2} \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (x)}{\sqrt{a}}\right )}{\sqrt{a} b^3}-\frac{(4 a+7 b) \cos (x) \sin (x)}{8 b^2}-\frac{\cos ^3(x) \sin (x)}{4 b}\\ \end{align*}
Mathematica [A] time = 0.188778, size = 79, normalized size = 0.91 \[ \frac{(a+b)^{5/2} \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (x)}{\sqrt{a}}\right )}{\sqrt{a} b^3}-\frac{4 x \left (8 a^2+20 a b+15 b^2\right )+8 b (a+2 b) \sin (2 x)+b^2 \sin (4 x)}{32 b^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.085, size = 202, normalized size = 2.3 \begin{align*} -{\frac{ \left ( \tan \left ( x \right ) \right ) ^{3}a}{2\,{b}^{2} \left ( \left ( \tan \left ( x \right ) \right ) ^{2}+1 \right ) ^{2}}}-{\frac{7\, \left ( \tan \left ( x \right ) \right ) ^{3}}{8\,b \left ( \left ( \tan \left ( x \right ) \right ) ^{2}+1 \right ) ^{2}}}-{\frac{\tan \left ( x \right ) a}{2\,{b}^{2} \left ( \left ( \tan \left ( x \right ) \right ) ^{2}+1 \right ) ^{2}}}-{\frac{9\,\tan \left ( x \right ) }{8\,b \left ( \left ( \tan \left ( x \right ) \right ) ^{2}+1 \right ) ^{2}}}-{\frac{\arctan \left ( \tan \left ( x \right ) \right ){a}^{2}}{{b}^{3}}}-{\frac{5\,\arctan \left ( \tan \left ( x \right ) \right ) a}{2\,{b}^{2}}}-{\frac{15\,\arctan \left ( \tan \left ( x \right ) \right ) }{8\,b}}+{\frac{{a}^{3}}{{b}^{3}}\arctan \left ({ \left ( a+b \right ) \tan \left ( x \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}}+3\,{\frac{{a}^{2}}{{b}^{2}\sqrt{a \left ( a+b \right ) }}\arctan \left ({\frac{ \left ( a+b \right ) \tan \left ( x \right ) }{\sqrt{a \left ( a+b \right ) }}} \right ) }+3\,{\frac{a}{b\sqrt{a \left ( a+b \right ) }}\arctan \left ({\frac{ \left ( a+b \right ) \tan \left ( x \right ) }{\sqrt{a \left ( a+b \right ) }}} \right ) }+{\arctan \left ({ \left ( a+b \right ) \tan \left ( x \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}} \right ){\frac{1}{\sqrt{a \left ( a+b \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.51328, size = 775, normalized size = 8.91 \begin{align*} \left [\frac{2 \,{\left (a^{2} + 2 \, a b + b^{2}\right )} \sqrt{-\frac{a + b}{a}} \log \left (\frac{{\left (8 \, a^{2} + 8 \, a b + b^{2}\right )} \cos \left (x\right )^{4} - 2 \,{\left (4 \, a^{2} + 5 \, a b + b^{2}\right )} \cos \left (x\right )^{2} - 4 \,{\left ({\left (2 \, a^{2} + a b\right )} \cos \left (x\right )^{3} -{\left (a^{2} + a b\right )} \cos \left (x\right )\right )} \sqrt{-\frac{a + b}{a}} \sin \left (x\right ) + a^{2} + 2 \, a b + b^{2}}{b^{2} \cos \left (x\right )^{4} - 2 \,{\left (a b + b^{2}\right )} \cos \left (x\right )^{2} + a^{2} + 2 \, a b + b^{2}}\right ) -{\left (8 \, a^{2} + 20 \, a b + 15 \, b^{2}\right )} x -{\left (2 \, b^{2} \cos \left (x\right )^{3} +{\left (4 \, a b + 7 \, b^{2}\right )} \cos \left (x\right )\right )} \sin \left (x\right )}{8 \, b^{3}}, -\frac{4 \,{\left (a^{2} + 2 \, a b + b^{2}\right )} \sqrt{\frac{a + b}{a}} \arctan \left (\frac{{\left ({\left (2 \, a + b\right )} \cos \left (x\right )^{2} - a - b\right )} \sqrt{\frac{a + b}{a}}}{2 \,{\left (a + b\right )} \cos \left (x\right ) \sin \left (x\right )}\right ) +{\left (8 \, a^{2} + 20 \, a b + 15 \, b^{2}\right )} x +{\left (2 \, b^{2} \cos \left (x\right )^{3} +{\left (4 \, a b + 7 \, b^{2}\right )} \cos \left (x\right )\right )} \sin \left (x\right )}{8 \, b^{3}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.11581, size = 177, normalized size = 2.03 \begin{align*} -\frac{{\left (8 \, a^{2} + 20 \, a b + 15 \, b^{2}\right )} x}{8 \, b^{3}} + \frac{{\left (a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )}{\left (\pi \left \lfloor \frac{x}{\pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (2 \, a + 2 \, b\right ) + \arctan \left (\frac{a \tan \left (x\right ) + b \tan \left (x\right )}{\sqrt{a^{2} + a b}}\right )\right )}}{\sqrt{a^{2} + a b} b^{3}} - \frac{4 \, a \tan \left (x\right )^{3} + 7 \, b \tan \left (x\right )^{3} + 4 \, a \tan \left (x\right ) + 9 \, b \tan \left (x\right )}{8 \,{\left (\tan \left (x\right )^{2} + 1\right )}^{2} b^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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